Files
curriculum-project-hub/examples/TH-141/lemmas/立方格子下zeta具体值/proof.typ
T
sjfhsjfh c73a2c903f feat(examples): migrate TH-141 sample to declarative layout (WU-6)
Real-content fixture for the end-to-end pipeline. TH-141 (39 parts: 22 segment,
15 lemma, 2 example) migrated from the prototype's typst `#let parts` manifest
to ADR-0008: declarative manifest.toml (project+info+ordered parts+targets) +
per-element element.toml (kind + scalars; examples carry `source`). Content .typ
files copied byte-identical (no math corruption); per-element main.typ + meta.toml
dropped (wiring is now generated). Part order matches source exactly; 5 lemmas
have no proof.typ (optional); no cross-file imports / paralearn refs / figs.

Co-Authored-By: Claude Opus 4.8 (1M context) <noreply@anthropic.com>
2026-06-22 01:33:40 +08:00

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Typst

数缺键以几何方式进行。
简单立方中每个体相原子的 6 个最近邻分布在上下左右前后六个方向。(100) 面上的表面原子失去上方那 1 个邻居,故 $Z_s = 5$$zeta = 5\/6$
面心立方中每个体相原子的 12 个最近邻分布在该原子周围三个 (111) 面上。(111) 面是最密堆积,表面原子失去上方一层的 3 个邻居,$Z_s = 9$$zeta = 3\/4$。(100) 面失去 4 个上方邻居,$Z_s = 8$$zeta = 2\/3$。(110) 面失去的近邻更多,$zeta$ 进一步减小。