Files
curriculum-project-hub/examples/TH-141/examples/41届复赛三-2-缺键模型/solution.typ
T
sjfhsjfh c73a2c903f feat(examples): migrate TH-141 sample to declarative layout (WU-6)
Real-content fixture for the end-to-end pipeline. TH-141 (39 parts: 22 segment,
15 lemma, 2 example) migrated from the prototype's typst `#let parts` manifest
to ADR-0008: declarative manifest.toml (project+info+ordered parts+targets) +
per-element element.toml (kind + scalars; examples carry `source`). Content .typ
files copied byte-identical (no math corruption); per-element main.typ + meta.toml
dropped (wiring is now generated). Part order matches source exactly; 5 lemmas
have no proof.typ (optional); no cross-file imports / paralearn refs / figs.

Co-Authored-By: Claude Opus 4.8 (1M context) <noreply@anthropic.com>
2026-06-22 01:33:40 +08:00

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Typst

完整推导见 @缺键一般式。要点为:设体相分子最近邻数 $Z$、单键能 $epsilon$,由共享键计数得 $epsilon = 2 L_m \/ (N_A Z)$;表面分子缺 $(1 - zeta) Z$ 根键,按半键计赔账得亏损能 $Delta U = (1 - zeta) L_m \/ N_A$;分子占体积 $d^3 = mu \/ (rho N_A)$ 给出面密度 $n_s = (rho N_A \/ mu)^(2\/3)$。代入 @骨架公式
$ sigma = Delta U dot n_s = (1 - zeta) thin L_m thin rho^(2\/3) / (mu^(2\/3) thin N_A^(1\/3)) . $